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InterviewSolution
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When circular scale of a screw gauge carrying 100 divisions is given four complete rotation, the head of the screw moves through 2mm. Calculate pitch and least count of the screw gauge. |
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Answer» Here, no of divisions on circular scale =100 no. of complete rotations = 4 distacne moved =2mm. ` Pitch = ("distance moved")/("no. of complete rotations") = (2mm)/(4)` 0.5mm Least count =` ("Pitch")/("no. ofn divisions on circular scale")` `=(0.5mm)/(100) = 0.005mm` |
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