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When `Cl_(2)` gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes fromA. Zero to `-1` and zero to `+3`B. Zero to `+1` and zero to `-3`C. Zero to `+1` and zero to `-5`D. Zero to `-1` and zero to `+5` |
Answer» Correct Answer - D `underset("O.N.=0)(Cl_(2))+NaOHrarrunderset(-1)(Cl)^(Theta)+underset(+5)(ClO_(3))^(Theta)` |
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