When composite rod is free, then composite length increases to 2.002 m for temperature `20^(@)C` to `120^(@)C` when composite rod is fixed between the support there is no change in component length find y and `alpha` of steel, if `y_(c)=1.5xx10^(13)N//m^(2)alpha_(c)=1.6xx10^(-5)//.^(@)C`.

When composite rod is free, then composite length increases to 2.002

1.	When composite rod is free, then composite length increases to 2.002 m for temperature `20^(@)C` to `120^(@)C` when composite rod is fixed between the support there is no change in component length find y and `alpha` of steel, if `y_(c)=1.5xx10^(13)N//m^(2)alpha_(c)=1.6xx10^(-5)//.^(@)C`.
Answer» `Deltal=l_(S)alpha_(S)DeltaT+l_(C)alpha_(C)DeltaTimplies0.002=[1.5alpha_(S)+0.5xx1.6xx10^(-5)]xx100` `impliesalpha_(S)=(1.2xx10^(-5))/(1.5)=8xx10^(-6)// .^(@)C` there is no change in compoenent length

Discussion

No Comment Found

Related InterviewSolutions

The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through an angle of `30^@`. Then angle of shear isA. `12^(@)`B. `0.12^(@)`C. `1.2^(@)`D. `0.012^(@)`
When a weight of `10 kg` is suspended from a copper wire of length 3 metres and diameters `0.4 mm`, its length increases by `2.4 cm`. If the diameter of the wire is doubled, then the extension in its length will beA. `9.6 cm`B. `4.8 cm`C. `1.2 cm`D. `0.6 cm`
In a wire of length L, the increase in its length is `l`. If the length is reduced to half, the increase in its length will beA. Reduced by halfB. Increase by halfC. Remains sameD. None of these
A wire of length 2.5 m has a percentage strain of 0.012% under a tensile force. The extension produce in the wire will beA. 0.03 mmB. 0.3 mmC. 0.3 mmD. 0.03 m
Two bars A and B are stuck using an adhesive. The contact surface of the bars make an angle q with the length. Area of cross section of each bar is `S_(0)`. It is known that the adhesive yields if normal stress at the contact surface exceeds `sigma_(0)`. Find the maximum pulling force F that can be applied without detaching the bars.
Find the greatest length of steel wire that can hang vertically without breaking.Breaking stress of steel `=8.0xx10^(8) N//m^(2)`. Density of steel `=8.0xx10^(3) kg//m^(3)`. Take `g =10 m//s^(2)`.
The breaking stress of a wire is `7.2xx10^(8)N//m^(2)` and density is `78xx10^(2) kg//m^(3)`. The wire is held vertically to the rigid support. The maximum length so that the wire does not break isA. `9.94xx10^(3)m`B. `9.4xx10^(3)m`C. `94xx10^(3)`mD. `940xx10^(3)`m
Elasticity is the property of material body by virtue of which a bodyA. occupies minimum surface areaB. is in equilibriumC. opposes its deformationD. attracts other bodies
The property of a body by virtue of which it changes its dimensions permanently is calledA. plasticityB. elasticityC. rigidityD. None of these
The nature of elastic forces by virtue of which a body possess the property of elasticity isA. electromagneticB. gravitationalC. weakD. all of the above

When composite rod is free, then composite length increases to 2.002 m for temperature `20^(@)C` to `120^(@)C` when composite rod is fixed between the support there is no change in component length find y and `alpha` of steel, if `y_(c)=1.5xx10^(13)N//m^(2)alpha_(c)=1.6xx10^(-5)//.^(@)C`.

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment