When conc. H_(2)SO_(4) was treated with K_(4) [Fe(CN)_(6)], CO has was evolved. By mistake, somebody used dilute H_(2)SO_(4) instead of conc, H_(2)SO_(4), then the gas evolved was

When conc. H_(2)SO_(4) was treated with K_(4) [Fe(CN)_(6)], CO has was

1.	When conc. H_(2)SO_(4) was treated with K_(4) [Fe(CN)_(6)], CO has was evolved. By mistake, somebody used dilute H_(2)SO_(4) instead of conc, H_(2)SO_(4), then the gas evolved was
Answer» `CO` `HCN` `N_(2)` `CO_(2)` Solution :`K_(4)[Fe(CN)_(6)]+underset("conc.")(6H_(2)SO_(4))+6H_(2)O RARR 2K_(2)SO_(4)+FeSO_(4)+3(NH_(4))_(2)SO_(4)+6CO uarr` `K_(4)[Fe(CN)_(6)]+underset("(dil.)")(3H_(2)SO_(4)) rarr 2K_(2)SO_(4)+FeSO_(4)+6HCN uarr`