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When copper is treated with a certain concentration of nitric acid, nitric oxide and nitrogen dioxide are liberated in equal volumes according to the following equation xCu + yHNO_(3)rarr Cu(NO_3)_2 + NO + NO_2 + H_(2)O . The coefficient of x is ______ |
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Answer» `3Cu+8HNO_3Cu(NO_3)_(2)+2NO+4H_(2)O...(i)` `Cu+4HNO_(3) rarr Cu(NO_3)_(2)+2NO_(2)+2H_(2)O....(ii)` Here NO and `NO_2`are EVOLVED in equal volumes, therefore , adding Eqns. (i) and (ii) , have `4Cu + 12 HNO_3 rarr 4Cu(NO_3)_(2) +2NO_2 +2NO + 6H_(2)O " or " 2Cu+6HNO_3 rarr 2Cu(NO_3)_(2) +NO_2 +NO+3H_2O` Thus coefficients X and y of `Cu and HNO_3`respectively are 2 and 6. |
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