When `Cu^(2+)` ion is treated with KI,a white precipiate is formed. Ex – InterviewSolution

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1.	When `Cu^(2+)` ion is treated with KI,a white precipiate is formed. Explain the reaction with the help of chemical equation .
Answer» `i^(-)` ion is a strong reducing agent. It reduces `Cu^(2+)` to `Cu^(+)` `2Cu^(2+) + 4I^(-) rarr underset("(white ppt.)")(Cu_(2)I_(2)) + I_(2)`

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