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When current in a coil changes from 5 A to 2 A in 0.1 s, average voltage of 50 V is produced. The self - inductance of the coil is :A. `1.67H`B. `6H`C. `3H`D. `0.67H` |
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Answer» Correct Answer - A `EMF=(Ldi)/(dt)` `50=L(5-2)/(0.1 "sec")` `implies L=(50xx0.1)/3=5/3=1.67H` |
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