When current passes through resistor due to its resistive property heat is produced. Error in measurement of resistance, current and time is 1%, 2% and 1% respectively, then what will be percentage error in measurement of heat energy ?

When current passes through resistor due to its resistive property hea

1.	When current passes through resistor due to its resistive property heat is produced. Error in measurement of resistance, current and time is 1%, 2% and 1% respectively, then what will be percentage error in measurement of heat energy ?
Answer» 4 6 5 8 Solution :`H=(I^(2)Rt)/(?J)` `:.` Percentage error in measurement of heat energy, J=constant `=(DeltaH)/(H)xx100%=((2DeltaI)/(I)+(DELTAR)/(R)+(Deltat)/(t))xx100%` `=(2xx2)%+1%+1%` =6%