1.

When electricity is passed through H_(2)SO_(4) and CaCl_(2) solution, the ratio of hydrogen and calcium liberated by weight will be(atomic mass of Ca = 40)

Answer»

`1:10`
`1:40`
`1:20`
`1:30`

Solution :Equivalent WEIGHT of `H_(2)` =1 and Equivalent weight of CA =`(40)/(2) =20`
`therefore ` RATIO of weights OBTAINED will be `1:20`


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