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When equal volumes of the following solutions are mixed, precipitation of AgCl (Ksp = 1⋅8 × 10−10) will occur only with : (a) 10−10 M (Ag+ ) and 10−10 M (Cl− ) (b) 10−4 M (Ag+) and 10−4 M (Cl− ) (c) 10−5 M (Ag+) and 10−5 M (Cl−) (d) 10−5 M (Ag+ ) and 10−6 M (Cl−) |
Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (b) 10<sup>−4</sup> M (Ag<sup>+</sup>) and 10<sup>−4</sup> M (Cl<sup>− </sup>)</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Ionic product = [Ag<sup>+</sup> ][Cl<sup>−</sup> ] = 10<sup>−4</sup> × 10<sup>−4</sup> = 10<sup>−8 </sup></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">It is more than its given ionic product (1.8 × 10<sup>−10</sup>)</span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">∴ So precipitation of AgCl will occur only with 10<sup>−4</sup> M(Ag<sup>+ </sup>) and 10<sup>−4 </sup> M(Cl <sup>−</sup> )</span></span></p> | |