When equal volumes of the following solutions are mixed, precipitation of `AgCl (K_(sp) = 1.8 xx 10^(-10))` will occur only withA. `10^(-4) M (Ag^(+))` and `10^(-4) M (Cl^(-))`B. `10^(-5) M (Ag^(+))` and `10^(-5) M(Cl^(-))`C. `10^(-6) M (Ag^(+))` and `10^(-6) M (Cl^(-))`D. `10^(-10) M (ag^(+))` and `10^(-10) M (Cl^(-))`

When equal volumes of the following solutions are mixed, precipitation

1.	When equal volumes of the following solutions are mixed, precipitation of `AgCl (K_(sp) = 1.8 xx 10^(-10))` will occur only withA. `10^(-4) M (Ag^(+))` and `10^(-4) M (Cl^(-))`B. `10^(-5) M (Ag^(+))` and `10^(-5) M(Cl^(-))`C. `10^(-6) M (Ag^(+))` and `10^(-6) M (Cl^(-))`D. `10^(-10) M (ag^(+))` and `10^(-10) M (Cl^(-))`
Answer» Correct Answer - A Ionic product `= [Ag^(+)][Cl^(-)] = (10^(-4))/(2) xx (10^(-4))/(2) = 2.5 xx 10^(-9) gt K_(sp)` (`because` equal volumes are mixed, so `[Ag^(+)] = (10^(-4))/(2)` and `[Cl^(-)] = (10^(-4))/(2)`)

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