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When excess of `SnCl_(2)` is added to a solution of `HgCl_(2)`, a white precipitate turning to gray is obtained. The grey colour is due toA. `Hg_(20Cl_(2)`B. `SnCl_(4)`C. SnD. Hg |
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Answer» Correct Answer - D `SnCl_(2)+underset(("Excess"))(HgCl_(2))rarrunderset(("grey""))(Hg)+SnCl_(4)` |
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