When forces F_(1), F_(2) and F_(3) are acting on a particle of mass m such that F_(2) and F_(3) are m utually perpendicular, then the particle remains stationary. If the force F x is now removed, then the acceleration of the particle is .........

When forces F_(1), F_(2) and F_(3) are acting on a particle of mass m

1.	When forces F_(1), F_(2) and F_(3) are acting on a particle of mass m such that F_(2) and F_(3) are m utually perpendicular, then the particle remains stationary. If the force F x is now removed, then the acceleration of the particle is .........
Answer» `(R_(3))/(m)` `(R_(1)+R_(2))/(m)` `(R_(1)-R_(2))/(m)` `(R_(1))/(m)` Solution :In equilibriumresultant of`R_(1) ` and `R_(2)` is `R_(3) ` andwill be inoppositedirection `R_(3) = sqrt(R_(1)^(2) + R_(2)^(2))` Nowacceleration`=("resultant force" ) /( " MASS ")` `a= (R_(3))/(m ) = (sqrt(R_(1)^(2) + R_(2)^(2))/( m ))`