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When Four Fair Dice Are Rolled Simultaneously, In How Many Outcomes Will At Least One Of The Dice Show 3? |
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Answer» When 4 dice are rolled simultaneously, there will be a total of 6 x 6 x 6 x 6 = 1296 OUTCOMES. The number of outcomes in which none of the 4 dice show 3 will be 5 x 5 x 5 x 5 = 625 outcomes. Therefore, the number of outcomes in which at least ONE DIE will show 3 = 1296 – 625 = 671. When 4 dice are rolled simultaneously, there will be a total of 6 x 6 x 6 x 6 = 1296 outcomes. The number of outcomes in which none of the 4 dice show 3 will be 5 x 5 x 5 x 5 = 625 outcomes. Therefore, the number of outcomes in which at least one die will show 3 = 1296 – 625 = 671. |
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