When four positive numbers a, b, c, and d are divided by 41, the remai

1.	When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively. When (5a + 6b – 2c + 10d) is divided by 41, then, the remainder will be – 1. 52. 73. 64. 17
Answer» Correct Answer - Option 3 : 6 GIVEN: When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively. CONCEPT: Dividend = Divisor x Quotient + Remainder CALCULATION: a = 41w + 3, b = 41x + 4, c = 41y + 6, d = 41z + 2 Here, 41w, 41x, 41y and 41z is divisible by 41. So, according to question – (5a + 6b – 2c + 10d) ⇒ (15 + 24 – 12 + 20) ⇒ 59 – 12 ⇒ 47 When (5a + 6b – 2c + 10d) is divided by 41. ⇒ Remainder (47/41) = 6

When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively. When (5a + 6b – 2c + 10d) is divided by 41, then, the remainder will be – 1. 52. 73. 64. 17

Answer» Correct Answer - Option 3 : 6

GIVEN:

When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively.

CONCEPT:

Dividend = Divisor x Quotient + Remainder

CALCULATION:

a = 41w + 3, b = 41x + 4, c = 41y + 6, d = 41z + 2

Here, 41w, 41x, 41y and 41z is divisible by 41.

So, according to question –

(5a + 6b – 2c + 10d)

⇒ (15 + 24 – 12 + 20)

⇒ 59 – 12

⇒ 47

When (5a + 6b – 2c + 10d) is divided by 41.

⇒ Remainder (47/41) = 6

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When four positive numbers a, b, c, and d are divided by 41, the remainders are 3, 4, 6, and 2, respectively. When (5a + 6b – 2c + 10d) is divided by 41, then, the remainder will be – 1. 52. 73. 64. 17

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