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When gold crystallizes to form body-centred cubic cells. The unit cell edge length is 308 pm. Calculate the density of gold. Molar mass of gold is 197 g/ mol. |
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Answer» Gold crystalized in body-centered cubic cells it means number of atoms per unit cells=2. \(\therefore\) Density of Au \(=\frac{Ƶ M_{Au}}{a^3 N_A}\) \(= \frac{2\times197}{(308)^3\times(10^{-12})^3\times6.02\times10^{23}}\) \(=\frac{394}{2.92\times10^{-29}\times6.02\times10^{23}}\) \(=\frac{394}{17.58\times 10^{-6}}\) \(=22.4\times10^6 g/m^3\) or \(=22.4 \,g/cm^3\) |
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