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When `H_(2)O_(2)` is added to an acidified solution of `K_(2)Cr_(2)O_(7)`:A. Solution turns green due to formation of `Cr_(2)O_(3)`B. Solution turns yellow due to formation of `K_(2)CrO_(4)`C. Solution gives green ppt of `Cr(OH)_(3)`D. |
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Answer» Correct Answer - C `Cr_(2)O_(7)^(2-)+2H^(+)+4H_(2)O_(2) to 2CrO(O_(2))_(2)("blue coloured")+5H_(2)O`. |
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