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When H_(2)O_(2) react with N_(2)H_(4) then H_(2)O_(2) oxidised N_(2)H_(4). The no. of mole of H_(2)O_(2) required to oxidised 64gm N_(2)H_(4). |
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Answer» `N_(2)H_(4)+2[O]rarr N_(2)UARR +2H_(2)O` `UL(BAR(N_(2)H_(4)+2H_(2)O rarrN_(2)uarr+4H_(2)O))` |
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