When H_(2)S is passed through Hg_(2)^(2+), we get :

1.	When H_(2)S is passed through Hg_(2)^(2+), we get :
Answer» `HGS` `HgS + Hg_(2)S` `HgS + Hg` `Hg_(2)S` Solution :`Hg_(2)Cl_(2) + H_(2)S RARR 2HCl + underset((PPT))(HgS) + Hg`

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