1.

When H_(2)S is passed through Hg_(2)^(2+), we get :

Answer»

`HGS`
`HgS + Hg_(2)S`
`HgS + Hg`
`Hg_(2)S`

Solution :`Hg_(2)Cl_(2) + H_(2)S RARR 2HCl + underset((PPT))(HgS) + Hg`


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