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When `K_(4)[Fe(CN)_(6)]` is added to `FeCl_(3)` , the complex compound formed is:A. `Fe_(3)[Fe(CN)_(6)]_(4)`B. `Fe_(4)[Fe(CN)_(6)]_(3)`C. `K_(2)Fe[Fe(CN)_(6)]`D. `K_(2)Fe_(2)[Fe(CN)_(6)]_(2)` |
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Answer» Correct Answer - B `Fe^(3+)+[Fe(CN)_(6)]^(4-)toFe_(4)[Fe(CN)_(6)]_(3)` (prussian blue). |
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