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When `KMnO_(4)` is reduced with oxalic acid in acidic solution, the oxidation number of `Mn` changes fromA. 7 to 4B. 6 to 4C. 7 to 2D. 4 to 2 |
Answer» Correct Answer - C `{:(" COOH"),(5" | " +2 Koverset(+7)(M)nO_(4)+3H_(2)SO_(4) rarr K_(2)SO_(4)+2 overset(+2)(M)nSO_(4)+10 CO_(2) +8 H_(2)O),(" COOH"):}` In this reaction oxidation state of Mn change from +7 to +2. |
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