1.

When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will beA. `30^(@)`B. `75^(@)`C. `90^(@)`D. `60^(@)`

Answer» Correct Answer - B
(d) refractive index of prism,
`µ=(sin""(A+delta_(m))/2)/(sin""A/2)rArri=45^(@)=(A+delta_(m))/2`
So, `sin45^(@)/sin(A//2)=sqrt2`
So, `1/2=sin""A/2rArrA=60^(@)`


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