1.

When lithium is irradiated with light, one finds a stopping potential of 1.83V for lambda = 3000A^@ and 0.80V for lambda = 4000A^@. With the known charge on the electron, the work function of lithium is

Answer»

4.6eV
`3.68xx10^(-19) J`
`2.3 EV`
`1.2 eV`

SOLUTION :`(hC)/(lambda_1) = W_0 = KE_1 , (hC)/(lambda_2) = W_0 + KE_2`
`therefore W_0 = 2.3 eV`


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