1.

When N_(2) molecule accept electron and form N_(2)^(-) then added electron enter in ...... orbital.

Answer»

Antibonding `(sigma^(**)) `MOLECULAR orbital
Bonding `(PI)` molecular
Bonding `(sigma)` molecular
Antibonding`pi^(**)` molecular orbital

Solution :Antibonding`pi^(**)` molecular orbital
Now, `N_(2)` accept electron and FORM`N_(2)^(-)` Then total electron are 15.
`N_(2)^(-) = (pi_(2p_(x))^(**) )^(1)`because the next molecular orbital after `sigma_(2p_(z)) ` is `pi_(2p_(x))^(*) = pi_(2p_(y))^(**)`.Thus accepted electron `N_(2)`is filled in antiboncting molecular `pi_(2p_(x))^(**)` .


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