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When .n.number of particles of masses m, 2m, 3m, .... nm are at distances x_(1)=1,x_(2)=4,x_(3)=9,......x_(n)=n^(2) units respectively from origin on the x-axis, then find the distance of their centre of mass from origin |
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Answer» SOLUTION :`x_(cm)=(m(1)+2M(4)+3m(9)+.........+nm(n^(2)))/(m+2m+3m+......+nm)` `=(m(1+2^(3)+3^(3)+......+n^(3)))/(m(1+2+3+.......+n))` `=(((n(n+1))/(2))^(2))/((n(n+1))/(2))=(n(n+1))/(2)` |
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