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When `Na_(2)S_(2)O_(3)` is reacted with `I_(2)` to form `Na_(2)S_(4)O_(6)` and Nal then which statement is correct ?A. n-factor for `Na_(2)S_(2)O_(3)` is oneB. n-factor for `I_(2)` is twoC. 2 moles of `Na_(2)S_(2)O_(3)` is reacted with one mole of `I_(2)`D. n-factor for `Na_(2)S_(4)O_(6)` is one |
Answer» Correct Answer - A::B::C | |