1.

When NH_(4)Cl is not used together with NH_(4)OH in group-III reagent which of the following cation will not be precipitated?

Answer»

`Fe^(2+)`
`Cr^(3+)`
`Zn^(2+)`
`NH_(3)` soln.

Solution :In the absence of `NH_(4)^(+)` IONS or `NH_(4)Cl`, DISSOCIATION of `NH_(4)OH` is large i.e., concentration of `OH^(-)` is considerable to increase ionic products of hydroxides of `Fe^(2+),Cr^(3+) and Zn^(2+)` from their respective `K_(SP)`valeus, hence they will precipitate in `III^(rd)` group. however, `Ba(OH)_(2)` is SOLUBLE due to high `K_(sp)` value.


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