1.

When NH_(4)NO_(2)(s) decomposes at373K , it forms N_(2)(g) and H_(2)O(g). The DeltaH . For the reactionat one atmosphericpressureand 373 K is -223.6 kJ mol^(-1)of NH_(4)NO_(2)(s) decomposed. What is the value of DeltaU for the reaction under the same conditions ?( Given R = 8.31 J K^(-1) mol^(-1))

Answer»


Solution :`NH_(4)NO_(2)(s) RARR N_(2)(g) + 2H_(2)O(g) , DELTA n_(g) = 3-0 =3`
`DELTAU = DeltaH - Deltan_(g) RT = - 223.6 kJ mol^(-1) - ( 3 mol) xx ( 8.314 xx 10^(-3) k J K^(-1) mol^(-1)) xx ( 373K)`
`= - 232 kJ mol^(-1)`


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