When one metre, one kg and one minute are taken as fundamental units, the magnitude of a force is 36 units. What is the value of this force on CGS system?

When one metre, one kg and one minute are taken as fundamental units,

1.	When one metre, one kg and one minute are taken as fundamental units, the magnitude of a force is 36 units. What is the value of this force on CGS system?
Answer» `10^(3)` dyne `10^(5)` dyne `10^(6)` dyne `10^(7)` dyne Solution : The dimensional formula of force is `[MLT^(-2)]` `:. a= 1, b= 1, c=-2` `n_(2)= n_(1)[(M_(1))/(M_(2))]^(a)[(L_(1))/(L_(2))]^(b)[(T_(1))/(T_(2))]^(c)= 36[(1KG)/(1g)]^(1)[(am)/(1CM)^(1)][(1min)/(1s)]^(-2)` `=36[(1000g)/(1g)]^(1)[(100CM)/(1cm)^(1)][(60S)/(1s)]^(-2)= (36 xx10^(3) xx 10^(2))/(3600)= 10^(3)` Hence, in the CGS system of units the value of given force is `10^(3)` dyne