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When one mole of a monoatomic ideal gas at initialtemperature T K expandsadiabatically from 1 litre to 2litres , the final temperature in Kelvin would be |
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Answer» <P>T or `(T_(2))/(T_(1))= ((V_(1))/(V_(2)))^(gamma-1)` or`(T_(2))/(T) = ((1)/(2))^((5)/(3)-1)= ( 1)/( 2^(2//3))` ( for monoatomic ideal gas , `gamma=(C_(p))/(C_(v))=((5//2)R)/((3//2)R)=(5)/(3))` `:. T_(2) =(T)/( 2^(2//3))` |
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