When p(x)=x3−ax2+x is divided by (x+a), the remainder is (a) 0 (b) a (c) 2a (d) 3a

When p(x)=x3−ax2+x is divided by (x+a), the remainder is (a) 0 (b) a

1.	When p(x)=x3−ax2+x is divided by (x+a), the remainder is (a) 0 (b) a (c) 2a (d) 3a
Answer» When $p (x) = x^{3} - a x^{2} + x$ is divided by (x+a), the remainder is (a) 0 (b) a (c) 2a (d) 3a