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When positive numbers x, y and z are divided by 31, the remainders are 17, 24 and 27, respectively. When (4x - 2y + 3z) is divided by 31, the remainder will be:1. 82. 193. 164. 9 |
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Answer» Correct Answer - Option 1 : 8 Given- When positive numbers x, y and z are divided by 31, the remainders are 17, 24 and 27 Concept Used- If a number (x) is divided by (a) leaves remainder (b), then x = a × n + b [where n is an integer] Calculation- Let the numbers be, x = 31 × 1 + 17 = 48 y = 31 × 1 + 24 = 55 z = 31 × 1 + 27 = 58 ⇒ (4x - 2y + 3z) = 256 Now, 256 = 31 × 8 + 8 ∴ When (4x - 2y + 3z) is divided by 31, the remainder will be 8 |
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