1.

When propanamide reacts with Br_(2) and NaOH then which of the following compounds is formed ?

Answer»

Ethyl alcohol
Propyl alcohol
Propyl amine
Ethylamine

Solution :`CH_(3)CH_(2)CONH_(2) underset(underset("REACTION")("Hoffmann bromamide"))overset(Br_(2) //KOH)(RARR) underset("Ethylamine")(CH_(3)CH_(2)NH_(2))`


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