1.

When propionic acid is treated with aqueous sodium bicarbonate CO_(2) is liberated. The 'C' of CO_(2) comes from

Answer»

methyl group
carboxylic acid group
methylene group
BICARBONATE

Solution :`UNDERSET("Propionic acid")(CH_(3)CH_(2)COOH (aq)) + underset("sod. bicarbonate")(NaHCO_(3) (aq)) rarr CH_(3) CH_(2) COONa + CO_(2) + H_(2)O`


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