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When quartile is a fraction Let us colculate Q_(1) from the following array. |
Answer» SOLUTION : `Q_(1)=(N+1)/(4)"th ITEM" =(20+1)/(4)"th item"=5.25"th item"` Value of 5th item = Rs. 66 Value of 6th item = Rs. 68 DIFFERENCE = Rs. 2 `(=68-66).` `thereforeQ_(1)=66+(25xx2)=66+0.5=66.5` |
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