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When S in the form of S_(g) is heated at 1000K, the initital pressure of 1 atm falls by 30% at equilibrium. This is because of conversion of some S_(g) to S_(2)(g) The K_(p) of the reaction is 0.011 "atm"^(-3) |
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Answer» <P>`2.96 "atm"^(3)` `t-t_("eqm")1 "atm"-0.3"atm" 1.2"atm"` `k_(p)=((1.2)^(4))/(0.7)=2.96 "atm"^(3)` =0.7atm |
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