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When S in the form of `S_(g)` is heated at 1000K, the initital pressure of 1 atm falls by 30% at equilibrium. This is because of conversion of some `S_(g)` to `S_(2)(g)` The `K_(p)` of the reaction is `0.011 "atm"^(-3)`A. `2.96 "atm"^(3)`B. `1.71"atm"^(3)`C. `204.8"atm"^(3)`D. None of these |
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Answer» `S_(g)(g)hArr4S_(2)(g)` `t-t_("eqm")1 "atm"-0.3"atm" 1.2"atm"` `k_(p)=((1.2)^(4))/(0.7)=2.96 "atm"^(3)` =0.7atm |
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