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When `SO_2` is passed through acidified `K_2Cr_2O_7` solutionA. the solution turns blueB. the solution is discolourisedC. `SO_2` is reducedD. green `Cr_2(SO_4)_3` is formed |
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Answer» Correct Answer - D `K_2Cr_2O_7 + H_2SO_4 + 3SO_4 to K_2SO_4 + underset"Green"(Cr_2(SO_4)_3) + H_2O` |
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