1.

When solution of 5g of iodine in CS_(2) was shaken with the same volume of water. The amount of iodine in water is (Distribution coefficient (C_(CS_(2)))/(C_(CS_(2)))=420

Answer»

`1.19`
`0.0019`
`0.0119`
`0.119`

Solution :Let the amount of iodine in water be a GM , `C_(1)=5g` in X MOL of `CS_(2), C_(2)-5-a` g in x ml of `H_(2)O`. Then `(5-a)/(a)=420`, thereforea=0.0118`


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