When sulphur in the form of S_8 is beated at 900K, the initial pressure of 1 atm falls by 29% at equilibrium. This is because of conversion of S_8 to S_2. Calculate the equilibrium constant for the reaction.

When sulphur in the form of S_8 is beated at 900K, the initial pressur

1.	When sulphur in the form of S_8 is beated at 900K, the initial pressure of 1 atm falls by 29% at equilibrium. This is because of conversion of S_8 to S_2. Calculate the equilibrium constant for the reaction.
Answer» Solution :`{:(,S_8(g)hArr , 4S_2(g)),("INITIAL pressure", 1,0),("Pressure at equil.",1-ALPHA, 4alpha):}` SINCE at equilibrium `alpha`=29%=0.29 `therefore p_(S_8)=1-alpha` =1-0.29=0.71 `p_(S_2)=4alpha` =4 x 0.29=1.16 `K_p=([p_(S_3)]^4)/p_(S_8)=(1.16)^4/0.71 = "2.55 ATM"^3`