When the angle of projection is 75^@ , a ball falls 10 m short of the target. When the angle of projection is 45^@ , it falls 10 m ahead of the target. Both are projected from the same point with the same speed in the same direction, the distance of the target from the point of projection is

When the angle of projection is 75^@ , a ball falls 10 m short of the

1.	When the angle of projection is 75^@ , a ball falls 10 m short of the target. When the angle of projection is 45^@ , it falls 10 m ahead of the target. Both are projected from the same point with the same speed in the same direction, the distance of the target from the point of projection is
Answer» 15 m 30 m 45 m 10 m Solution :Let d be the distance of the target from the POINT of projection. `:. (u^2 sin (2xx75^@))/g=d-10 "or " u^2/(2g)=d-10""...(i)` and `:. (u^2 sin (2xx45^@))/g=d+10 "or " u^2/(g)=d+10""...(II)` Divide (i) by (ii) , we get `(d-10)/(d+10)=1/2 " or " d = 30 m`