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When the aqueous solution of 0.5 mole `HNO_(3)` is mixed with the 0.3 mole of `OH^(-)` solution, then what will be the liberated heat (Enthalpy of neutralization is = 57.1 kJ)A. 28.5 kJB. 17.1 kJC. 45.7 kJD. 1.7 kJ |
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Answer» Correct Answer - B 0.3 mole `OH^(-)`, neutralize 0.3 mole of `HNO_(3)` Evolved heat, `=57.1xx0.3=17.13 kJ`. |
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