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When the distance between two charged particles is halved, the force between them will becomeA. one-thirdB. one-halfC. four timesD. five times |
Answer» Correct Answer - C `r_(2)=r_(1)/2,F_(2)=?` `Fprop1/r^(2)` `therefore" "F_(2)/F_(1)=(r_(1)/r_(2))^(2)=(r_(1)/(r_(1)/2))^(2)=4` `F_(2)=4F_(1)="four times"` |
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