When the kinetic energy of the body executing SHM is (1)/(3) of potential energy, the displacement is………….% of amplitude.

When the kinetic energy of the body executing SHM is (1)/(3) of potent

1.	When the kinetic energy of the body executing SHM is (1)/(3) of potential energy, the displacement is………….% of amplitude.
Answer» `33` `87` `67` `50` Solution :KINETIC ENERGY of a body EXECUTING SHM `=(1)/(2)m omega^(2) (A^(2)-x^(2))"""………"(1)` Potential energy `=(1)/(2) m omega^(2) x^(2)"""…….."(2)` Now from (1) and (2) `(1)/(2) m omega^(2) (A^(2)-x^(2))= (1)/(3)xx(1)/(2) m omega^(2) x^(2)` `therefore A^(2) -x^(2)= (x^2)/(3)` `therefore A^(2)= (4x^2)/(3)` `therefore x^(2) = (3)/(4) A^(2)` Here `x= (A)/(2)sqrt(3) = 0.866 A` = 87% amplitude.