When the length of a simple pendulum is increased by 21% what is the change in its time period?

When the length of a simple pendulum is increased by 21% what is the c

1.	When the length of a simple pendulum is increased by 21% what is the change in its time period?
Answer» SOLUTION :Expression for the time period of a simple pendulum`T= 2pisqrt((l)/(g))` When length changes from `l_(1)` to `l_(2)` time period changes from `T_(1)` to `T_(2)` keeping g constant. `(T_(2))/(T_(1))= sqrt((l_(2))/(l_(1))):. (T_(2))/(T_(1))= sqrt((121l)/(100l))= (11)/(10)= ((T_(2))/(T_(1))-1)= ((11)/(10)-1)= (1)/(10) implies (DeltaT)/(T)%= (1)/(10)XX100= 10%` `:.` Increase in time period = 10%