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When the number of turns in a toroidal coil is doubled, then the value of magnetic flux density will becomes-A. four timesB. eight timesC. halfD. double |
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Answer» Correct Answer - D `Bxx2piR=mu_(0) xxN.i` `B=(mu_(0).i)/(2piR).N` `B prop N` So the magnetic field will be double. |
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