1.

When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a is………………

Answer»

`(a)/(4)`
`(a)/(3)`
`(a)/(2)`
`(2a)/(3)`

SOLUTION :`(1)/(2)momega^(2)y^(2)=(1)/(4)((1)/(2)momega^(2)a^(2))impliesy=(a)/(2)`


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