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When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a isA. `a//4`B. `a//3`C. `a//2`D. `2a//3` |
Answer» Correct Answer - C Potential energy `= (1)/(2) m omega^(2)y^(2)=(1)/(4) xx (1)/(2) m omega^(2)a^(2)` `y^(2)=(a^(2))/(4)rArr y = +- (a)/(2)` |
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