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When the pressure acting on an oil of volume 0.5 lit is increased by 15 xx 10^(5)N m^(2) the change in volume is 0.3 cm^(3). Find the bulk modulus of oil. |
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Answer» Solution :Volume strain `=("change of volume")/("original volume")=(0.3)/(500)=3//5000` STRESS = Pressure change `=15xx10^(5)Nm^(2)` `:.` BULK MODULUS `=("stress")/("strain")=(15xx10^(5))/(3//5000)=25xx10^(8)N//m^(2)` So bulk of the oil `=0.25xx10^(10)N//m^(2)` |
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