1.

When the pressure and absolute temperature of 5L nitrogen are doubled, the gas would have a volume of :

Answer»

10L
5L
15L
20L

Solution :`p_(1) =p`, `p_(2) = 2p`,
`T_(1) = T, T_(2) = 2T`,
`V_(1) = 5L, V_(2) = ?`
`( \p_(1) V_(1))/( T_(1))= ( p _(2) V_(2))/( T_(2))`
or `V_(2) = ( p_(1) V_(1) T_(2))/( T_(1) p _(2))`
`= ( p XX 5 xx 2T )/( T xx 2p ) = 5L`


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